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Re: How to use output of a pipeline?

Posted by Alexandru Ionita on Feb 01, 2010; 11:06am
URL: https://discuss.orbeon.com/How-to-use-output-of-a-pipeline-tp1458650p1458672.html

Hello Robin,

I'm not sure that you can consume the response of a webservice from another xform instead of the calling source xform.

But, if you want to consume the response of the webservice in the same xform, watch here:

ref: http://www.orbeon.com/orbeon/doc/reference-xforms-functions#orbeon-extensions

xxforms:call-xpl

<xf:trigger appearance="xxforms:link">

<xf:label class="button"><xhtml:span class="Prufen">Prüfen</xhtml:span></xf:label>

<xf:action ev:event="DOMActivate">

<xf:insert nodeset="instance('formCheckMessages')"

origin="xxforms:call-xpl(

'<<link_to_the_XPL_file>>',

'formData',

instance('userResponse'), 'checkMessages')"/>

</xf:action>

</xf:trigger>

by this, you are inserting the response of a pipeline into a defined instance.

If this is what you are looking for, don't hesitate to ask for more details.

regards,

Alexandru

On Mon, Feb 1, 2010 at 12:30, Robin Diederen <[hidden email]> wrote:

Hello all,

I have this pipeline which produces a XML document after doing some SOAP calls; the pipeline is fired by a submission from a Xforms document.

Now I to use this XML document on another Xforms document and I’m wondering how I can access this data.

From my pageflow:

    <page id="search-general-submit" path-info="/search/search-general-submit" >
        <action action="search-general-perform.xpl">
              <result page="search-general-result" transform="oxf:xslt">
                  <data xsl:version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
                      <xsl:copy-of select="doc('input:instance')"></xsl:copy-of>
                  </data>
            </result>
         </action>
    </page>

My guess would be that I should an xforms:instance element in the consuming Xforms document referring to the data generated by the pipeline. Is that correct? If so, how would I refer to this data?

Best, Robin

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