position() in a repeat
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Hi All, Is it possible to reference another instance using
position() from within a repeat? I cannot get this to work successfully. In other words I’d like to use a repeat to reference
nodes in another instance at the same position. Ie., when repeating at position 2, reference position 2 in a
separate instance. <xforms:repeat nodeset="instance('main')/child"
id="repeat">
<xforms:output
value="position()">
<xforms:label>Position = </xforms:label> </xforms:output> <xforms:output
ref="instance('test')/test[position()]">
<xforms:label>Value = </xforms:label> </xforms:output>
</xforms:repeat> Here is a link to the full example: http://dl.lib.brown.edu/mwp/xforms/test2.xhtml Thanks, Mike -- You receive this message as a subscriber of the [hidden email] mailing list. To unsubscribe: mailto:[hidden email] For general help: mailto:[hidden email]?subject=help OW2 mailing lists service home page: http://www.ow2.org/wws |
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Hi Michael, We had a similar
issue, and solved it by using xxforms:evaluate to get to the other instance
data: This constructs an
XPath dynamically using the “id” attribute of the node we’re
looping on. It finds a node with the same id in another instance: … <xforms:output
ref=”xxforms:evaluate(concat('instance(''other-instance'')/somewhere/node[.
= ', @Id, ']'))" at="1"/> … Hope this helps, Gerrit From: Park, Michael
[mailto:[hidden email]] Hi All, Is it possible to reference another instance using
position() from within a repeat? I cannot get this to work successfully. In other words I’d like to use a repeat to reference
nodes in another instance at the same position. Ie., when repeating at position 2, reference position 2 in
a separate instance. <xforms:repeat
nodeset="instance('main')/child"
id="repeat">
<xforms:output
value="position()">
<xforms:label>Position = </xforms:label>
</xforms:output>
<xforms:output ref="instance('test')/test[position()]">
<xforms:label>Value = </xforms:label>
</xforms:output>
</xforms:repeat> Here is a link to the full example: http://dl.lib.brown.edu/mwp/xforms/test2.xhtml Thanks, Mike -- You receive this message as a subscriber of the [hidden email] mailing list. To unsubscribe: mailto:[hidden email] For general help: mailto:[hidden email]?subject=help OW2 mailing lists service home page: http://www.ow2.org/wws |
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Thx! I’d like to try it. However, I
haven’t seen any real docs on how to use it. I’ll break yours
apart and see if I can get it working. I won’t actually be using it in an
output. I just did that to test. -Mike From: Gerrit Germis
[mailto:[hidden email]] Hi Michael, We had a similar
issue, and solved it by using xxforms:evaluate to get to the other instance
data: This constructs an
XPath dynamically using the “id” attribute of the node we’re
looping on. It finds a node with the same id in another instance: … <xforms:output
ref=”xxforms:evaluate(concat('instance(''other-instance'')/somewhere/node[.
= ', @Id, ']'))" at="1"/> … Hope this helps, Gerrit From: Hi All, Is it possible to reference another instance using position()
from within a repeat? I cannot get this to work successfully. In other words I’d like to use a repeat to reference
nodes in another instance at the same position. Ie., when repeating at position 2, reference position 2 in
a separate instance. <xforms:repeat
nodeset="instance('main')/child"
id="repeat">
<xforms:output value="position()">
<xforms:label>Position = </xforms:label> </xforms:output>
<xforms:output ref="instance('test')/test[position()]">
<xforms:label>Value = </xforms:label>
</xforms:output>
</xforms:repeat> Here is a link to the full example: http://dl.lib.brown.edu/mwp/xforms/test2.xhtml Thanks, Mike -- You receive this message as a subscriber of the [hidden email] mailing list. To unsubscribe: mailto:[hidden email] For general help: mailto:[hidden email]?subject=help OW2 mailing lists service home page: http://www.ow2.org/wws |
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In reply to this post by Gerrit Germis-2
Thanks Gerrit! It worked when I changed it to: <xforms:output ref="xxforms:evaluate(
concat('instance(''test'')/test[', position(), ']') )"> From: Gerrit Germis
[mailto:[hidden email]] Hi Michael, We had a similar
issue, and solved it by using xxforms:evaluate to get to the other instance
data: This constructs an
XPath dynamically using the “id” attribute of the node we’re looping
on. It finds a node with the same id in another instance: … <xforms:output
ref=”xxforms:evaluate(concat('instance(''other-instance'')/somewhere/node[.
= ', @Id, ']'))" at="1"/> … Hope this helps, Gerrit From: Hi All, Is it possible to reference another instance using
position() from within a repeat? I cannot get this to work successfully. In other words I’d like to use a repeat to reference
nodes in another instance at the same position. Ie., when repeating at position 2, reference position 2 in
a separate instance. <xforms:repeat
nodeset="instance('main')/child"
id="repeat">
<xforms:output value="position()">
<xforms:label>Position = </xforms:label>
</xforms:output>
<xforms:output ref="instance('test')/test[position()]">
<xforms:label>Value = </xforms:label>
</xforms:output>
</xforms:repeat> Here is a link to the full example: http://dl.lib.brown.edu/mwp/xforms/test2.xhtml Thanks, Mike -- You receive this message as a subscriber of the [hidden email] mailing list. To unsubscribe: mailto:[hidden email] For general help: mailto:[hidden email]?subject=help OW2 mailing lists service home page: http://www.ow2.org/wws |
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In reply to this post by Park, Michael
Since the other solution works for you, then all is well. But there's another tool to add to your XPath toolbox, which is using a trivial for-loop to create a local variable.
The problem with the original XPath expression you had, "instance('test')/test[position()]", is that the "position()" method is being called in the context of the "instance('test')/test" node rather than the original context. To explain more fully, any time you have an XPath expression like "<XPath>[<number>]", that is a shorthand for "<XPath>[position() = <number>]" and it selects all those elements at <XPath> for which their position (among all nodes at <XPath>) is equal to <number>. In this case, it will select all those nodes matching the path "instance('test')/test" for which their position is equal to their position, namely all of them! Just to add to the confusion, I believe that only the first would show up in the output. The trick is to evaluate the position() first, to get a value, and then pass that value to the [<number>] predicate. So what you would use is "for $posision in position() return instance('test')/test[$position]". I hope this helps, and my explanation is not too woolly. Cheers, Dave Mc ----- Original Message ----- From: "Michael Park" <[hidden email]> To: [hidden email] Sent: 28 November 2007 05:52:31 o'clock (GMT+1200) Auto-Detected Subject: RE: [ops-users] position() in a repeat -- You receive this message as a subscriber of the [hidden email] mailing list. To unsubscribe: mailto:[hidden email] For general help: mailto:[hidden email]?subject=help OW2 mailing lists service home page: http://www.ow2.org/wws -- You receive this message as a subscriber of the [hidden email] mailing list. To unsubscribe: mailto:[hidden email] For general help: mailto:[hidden email]?subject=help OW2 mailing lists service home page: http://www.ow2.org/wws |
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Dave,
I really appreciate that. It clears up a lot of confusion. And you were correct on the output. I like the variable solution. I wasn't aware of the fact I could store it like that. I was thinking a variable is exactly what I needed. However, I've never seen that syntax used in xforms before. Could you point me to an example? Thanks! -Mike -----Original Message----- From: David McIntyre [mailto:[hidden email]] Sent: Tuesday, November 27, 2007 4:16 PM To: [hidden email] Subject: Re: [ops-users] position() in a repeat Since the other solution works for you, then all is well. But there's another tool to add to your XPath toolbox, which is using a trivial for-loop to create a local variable. The problem with the original XPath expression you had, "instance('test')/test[position()]", is that the "position()" method is being called in the context of the "instance('test')/test" node rather than the original context. To explain more fully, any time you have an XPath expression like "<XPath>[<number>]", that is a shorthand for "<XPath>[position() = <number>]" and it selects all those elements at <XPath> for which their position (among all nodes at <XPath>) is equal to <number>. In this case, it will select all those nodes matching the path "instance('test')/test" for which their position is equal to their position, namely all of them! Just to add to the confusion, I believe that only the first would show up in the output. The trick is to evaluate the position() first, to get a value, and then pass that value to the [<number>] predicate. So what you would use is "for $posision in position() return instance('test')/test[$position]". I hope this helps, and my explanation is not too woolly. Cheers, Dave Mc ----- Original Message ----- From: "Michael Park" <[hidden email]> To: [hidden email] Sent: 28 November 2007 05:52:31 o'clock (GMT+1200) Auto-Detected Subject: RE: [ops-users] position() in a repeat -- You receive this message as a subscriber of the [hidden email] mailing list. To unsubscribe: mailto:[hidden email] For general help: mailto:[hidden email]?subject=help OW2 mailing lists service home page: http://www.ow2.org/wws -- You receive this message as a subscriber of the [hidden email] mailing list. To unsubscribe: mailto:[hidden email] For general help: mailto:[hidden email]?subject=help OW2 mailing lists service home page: http://www.ow2.org/wws |
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Mike,
I don't know off-hand of any examples which use the trick specifically to pass a single variable to a predicate rather than to construct a sequence of values. But the reference for the syntax for the "for" expression, including examples, is at http://www.w3.org/TR/xpath20/#id-for-expressions. The key point is that the expression works perfectly well even when the ForClause is just a sequence with only one value. Cheers, Dave Mc. ----- Original Message ----- From: "Michael Park" <[hidden email]> To: [hidden email] Sent: 28 November 2007 10:42:28 o'clock (GMT+1200) Auto-Detected Subject: RE: [ops-users] position() in a repeat Dave, I really appreciate that. It clears up a lot of confusion. And you were correct on the output. I like the variable solution. I wasn't aware of the fact I could store it like that. I was thinking a variable is exactly what I needed. However, I've never seen that syntax used in xforms before. Could you point me to an example? Thanks! -Mike -- You receive this message as a subscriber of the [hidden email] mailing list. To unsubscribe: mailto:[hidden email] For general help: mailto:[hidden email]?subject=help OW2 mailing lists service home page: http://www.ow2.org/wws |
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Administrator
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In reply to this post by Park, Michael
As pointed out, this syntax is not part of XForms: it is part of XPath
2.0. Note that XPath 2.0 is not yet officially part of XForms, but the XForms Working Group at W3C hopes to integrate XPath 2.0 in XForms 2.0. At Orbeon, we don't think we can live with just XPath 1.0 so we have decided to support XPath 2.0. -Erik On Nov 27, 2007, at 1:42 PM, Park, Michael wrote: > Dave, > > I really appreciate that. It clears up a lot of confusion. And you > were correct on the output. > > I like the variable solution. I wasn't aware of the fact I could > store > it like that. I was thinking a variable is exactly what I needed. > However, I've never seen that syntax used in xforms before. Could you > point me to an example? > > Thanks! > -Mike > > -----Original Message----- > From: David McIntyre [mailto:[hidden email]] > Sent: Tuesday, November 27, 2007 4:16 PM > To: [hidden email] > Subject: Re: [ops-users] position() in a repeat > > Since the other solution works for you, then all is well. But there's > another tool to add to your XPath toolbox, which is using a trivial > for-loop to create a local variable. > > The problem with the original XPath expression you had, > "instance('test')/test[position()]", is that the "position()" method > is > being called in the context of the "instance('test')/test" node rather > than the original context. > > To explain more fully, any time you have an XPath expression like > "<XPath>[<number>]", that is a shorthand for "<XPath>[position() = > <number>]" and it selects all those elements at <XPath> for which > their > position (among all nodes at <XPath>) is equal to <number>. In this > case, it will select all those nodes matching the path > "instance('test')/test" for which their position is equal to their > position, namely all of them! Just to add to the confusion, I believe > that only the first would show up in the output. > > The trick is to evaluate the position() first, to get a value, and > then > pass that value to the [<number>] predicate. > > So what you would use is "for $posision in position() return > instance('test')/test[$position]". > > I hope this helps, and my explanation is not too woolly. > > Cheers, > > Dave Mc > > ----- Original Message ----- > From: "Michael Park" <[hidden email]> > To: [hidden email] > Sent: 28 November 2007 05:52:31 o'clock (GMT+1200) Auto-Detected > Subject: RE: [ops-users] position() in a repeat > > > -- > You receive this message as a subscriber of the [hidden email] > mailing list. > To unsubscribe: mailto:[hidden email] > For general help: mailto:[hidden email]?subject=help > OW2 mailing lists service home page: http://www.ow2.org/wws > > > -- > You receive this message as a subscriber of the [hidden email] > mailing list. > To unsubscribe: mailto:[hidden email] > For general help: mailto:[hidden email]?subject=help > OW2 mailing lists service home page: http://www.ow2.org/wws Orbeon Forms - Web Forms for the Enterprise Done the Right Way http://www.orbeon.com/ -- You receive this message as a subscriber of the [hidden email] mailing list. To unsubscribe: mailto:[hidden email] For general help: mailto:[hidden email]?subject=help OW2 mailing lists service home page: http://www.ow2.org/wws |
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