Position() in repeat

>
> Erik,
>
> The code you're provided doesn't work.
> The position() Xpath 2.0 function does not return the same result in a
> repeat loop inside or outside a select1 control.
> See my new attached example.(the label of the select1)
>
> Marc
>
>  >This is due to the way XPath works. In this expression:
>
>  >instance('listes-simple')/liste[@id=instance('instance')/choix[position
>  >()]/@value]/item
>
>  >a new context is created once you use "[...]", so position applies to
> the position within that context, which is by default 1.
>
>  >Maybe you can try something like this (XPath 2.0):
>
>  >for $position in position() return
>  >instance('listes-simple')/liste[@id=instance('instance')/choix[$positio
>  >n]/@value]/item
>
> -Erik

> Marc,
>
> Then try something like:
>
> instance('listes-simple')/liste[@id=instance('instance')/choix[count(xxforms:repeat-current('idxChoix')/preceding-sibling::*)
> + 1]/@value]/item
>
> This will be easier to express once we have XSLT-like variables in
> XForms.
>
> -Erik
>
> marc wrote:
>
>>
>> Erik,
>>
>> The code you're provided doesn't work.
>> The position() Xpath 2.0 function does not return the same result in
>> a repeat loop inside or outside a select1 control.
>> See my new attached example.(the label of the select1)
>>
>> Marc
>>
>>  >This is due to the way XPath works. In this expression:
>>
>>  >instance('listes-simple')/liste[@id=instance('instance')/choix[position
>>
>>  >()]/@value]/item
>>
>>  >a new context is created once you use "[...]", so position applies
>> to the position within that context, which is by default 1.
>>
>>  >Maybe you can try something like this (XPath 2.0):
>>
>>  >for $position in position() return
>>  >instance('listes-simple')/liste[@id=instance('instance')/choix[$positio
>>
>>  >n]/@value]/item
>>
>> -Erik
>