Can I sort by the label (ref by the value in xml) in exf:sort function

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Can I sort by the label (ref by the value in xml) in exf:sort function

James Gu
    <persons>
        <person>
            <id>p1</id>
        </person>
        <person>
            <id>p2</id>
        </person>
        <person>
            <id>p3</id>
        </person>
        <person>
            <id>p4</id>
        </person>
    </persons>

<xforms:repeat nodeset="exf:sort(/persons/person, 'id', 'text')">

I am trying to sort this xml. There are only primary keys in xml data and the names are stored in another xml instance. Can I sort by name (not id) in this function? Any suggestions will be appreciated.

    <Person key="p1">
        <PersonName>
            <FullName>Tom</FullName>
        </PersonName>
    </Person>
    <Person key="p2">
        <PersonName>
            <FullName>Jack</FullName>
        </PersonName>
    </Person>
    <Person key="p3">
        <PersonName>
            <FullName>Clark</FullName>
        </PersonName>
    </Person>
    <Person key="p4">
        <PersonName>
            <FullName>Mike</FullName>
        </PersonName>
    </Person>
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Re: Can I sort by the label (ref by the value in xml) in exf:sort function

Erik Bruchez
Administrator
I am not sure what the two XML fragments below are. Could you provide  
more information?

-Erik

On Jun 16, 2008, at 8:35 AM, James Gu wrote:

>
>    <persons>
>        <person>
>            <id>p1</id>
>        </person>
>        <person>
>            <id>p2</id>
>        </person>
>        <person>
>            <id>p3</id>
>        </person>
>        <person>
>            <id>p4</id>
>        </person>
>    </persons>
>
> <xforms:repeat nodeset="exf:sort(/persons/person, 'id', 'text')">
>
> I am trying to sort this xml. There are only primary keys in xml  
> data and
> the names are stored in another xml instance. Can I sort by name  
> (not id) in
> this function? Any suggestions will be appreciated.
>
>    <Person key="p1">
>        <PersonName>
>            <FullName>Tom</FullName>
>        </PersonName>
>    </Person>
>    <Person key="p2">
>        <PersonName>
>            <FullName>Jack</FullName>
>        </PersonName>
>    </Person>
>    <Person key="p3">
>        <PersonName>
>            <FullName>Clark</FullName>
>        </PersonName>
>    </Person>
>    <Person key="p4">
>        <PersonName>
>            <FullName>Mike</FullName>
>        </PersonName>
>    </Person>
> --
> View this message in context: http://www.nabble.com/Can-I-sort-by-the-label-%28ref-by-the-value-in-xml%29-in-exf%3Asort-function-tp17867017p17867017.html
> Sent from the ObjectWeb OPS - Users mailing list archive at  
> Nabble.com.
>
>
> --
> You receive this message as a subscriber of the [hidden email]  
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> To unsubscribe: mailto:[hidden email]
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Re: Can I sort by the label (ref by the value in xml) in exf:sort function

James Gu
These are the instances.
            <xforms:instance id="scorelist">
                <department>
                    <employee>
                        <personfk>p3</personfk>
                        <score>80</score>
                    </employee>
                    <employee>
                        <personfk>p4</personfk>
                        <score>70</score>
                    </employee>
                    <employee>
                        <personfk>p1</personfk>
                        <score>90</score>
                    </employee>
                    <employee>
                        <personfk>p2</personfk>
                        <score>100</score>
                    </employee>
                </department>
            </xforms:instance>

            <xforms:instance id="personlist">
                <persons>
                    <Person key="p1">
                        <PersonName>
                            <FullName>Tom</FullName>
                        </PersonName>
                    </Person>
                    <Person key="p2">
                        <PersonName>
                            <FullName>Jack</FullName>
                        </PersonName>
                    </Person>
                    <Person key="p3">
                        <PersonName>
                            <FullName>Clark</FullName>
                        </PersonName>
                    </Person>
                    <Person key="p4">
                        <PersonName>
                            <FullName>Mike</FullName>
                        </PersonName>
                    </Person>
                </persons>
            </xforms:instance>


This is the code to generate a table for instance list.

        <xhtml:table>
            <xforms:repeat nodeset="exf:sort(xxforms:instance('scorelist')/employee,'personfk','text')">
                <xhtml:tr>
                    <xhtml:td>
                        <xforms:output value="personfk"></xforms:output>
                    </xhtml:td>
                    <xhtml:td>
                        <xxforms:variable name="current-value" select="personfk"></xxforms:variable>
                        <xforms:output
                                value="saxon:evaluate(replace('xxforms:instance(''personlist'')/Person[@key=''%current-value%'']/PersonName/FullName', '%current-value%', $current-value))"></xforms:output>
                    </xhtml:td>
                    <xhtml:td>
                        <xforms:output value="score"></xforms:output>
                    </xhtml:td>
                </xhtml:tr>
            </xforms:repeat>
        </xhtml:table>

This is the result I got. My question is how can I sort by the second column (name). This column doesn't exist in the repeat nodeset, but I can get it from other instance because there is fk in nodeset. It is a lookup. Does exf:sort provide solution of this situation? Could you check it?

fk   name score

p1  Tom  90  

p2  Jack  100  

p3  Clark  80  

p4  Mike  70  

   
Thank you very much!
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RE: Re: Can I sort by the label (ref by the value in xml) in exf:sort function

Ryan Puddephatt-3
James,
        What about

<xhtml:table>
            <xforms:repeat
nodeset="exf:sort(xxforms:instance('personlist')/Person,'PersonName/FullName','text')">
                <xhtml:tr>
                    <xhtml:td>
                        <xforms:output value="@key"></xforms:output>
                    </xhtml:td>
                    <xhtml:td>
                        <xforms:output value="PersonName/Fullname"></xforms:output>
                    </xhtml:td>
                    <xhtml:td>
                        <xforms:output value="xxforms:instance('scorelist')/employee[personfk = current()/@key]/score"></xforms:output>
                    </xhtml:td>
                </xhtml:tr>
            </xforms:repeat>
        </xhtml:table>

Ryan

-----------------------------------------------
Ryan Puddephatt
FIX Developer
Fidessa LatentZero
1 Alfred Place
London WC1E 7EB
Office: +44 (0) 20 7462 4200
Direct: +44 (0) 20 7323 6112
Blackberry: +44 (0) 79 8539 2458
Fax: +44 (0) 20 7462 4242
Email: [hidden email]
Web: http://www.latentzero.com


-----Original Message-----
From: JamesGu [mailto:[hidden email]]
Sent: 20 June 2008 22:52
To: [hidden email]
Subject: [ops-users] Re: Can I sort by the label (ref by the value in xml) in exf:sort function


These are the instances.
            <xforms:instance id="scorelist">
                <department>
                    <employee>
                        <personfk>p3</personfk>
                        <score>80</score>
                    </employee>
                    <employee>
                        <personfk>p4</personfk>
                        <score>70</score>
                    </employee>
                    <employee>
                        <personfk>p1</personfk>
                        <score>90</score>
                    </employee>
                    <employee>
                        <personfk>p2</personfk>
                        <score>100</score>
                    </employee>
                </department>
            </xforms:instance>

            <xforms:instance id="personlist">
                <persons>
                    <Person key="p1">
                        <PersonName>
                            <FullName>Tom</FullName>
                        </PersonName>
                    </Person>
                    <Person key="p2">
                        <PersonName>
                            <FullName>Jack</FullName>
                        </PersonName>
                    </Person>
                    <Person key="p3">
                        <PersonName>
                            <FullName>Clark</FullName>
                        </PersonName>
                    </Person>
                    <Person key="p4">
                        <PersonName>
                            <FullName>Mike</FullName>
                        </PersonName>
                    </Person>
                </persons>
            </xforms:instance>


This is the code to generate a table for instance list.

        <xhtml:table>
            <xforms:repeat
nodeset="exf:sort(xxforms:instance('scorelist')/employee,'personfk','text')">
                <xhtml:tr>
                    <xhtml:td>
                        <xforms:output value="personfk"></xforms:output>
                    </xhtml:td>
                    <xhtml:td>
                        <xxforms:variable name="current-value"
select="personfk"></xxforms:variable>
                        <xforms:output
                               
value="saxon:evaluate(replace('xxforms:instance(''personlist'')/Person[@key=''%current-value%'']/PersonName/FullName',
'%current-value%', $current-value))"></xforms:output>
                    </xhtml:td>
                    <xhtml:td>
                        <xforms:output value="score"></xforms:output>
                    </xhtml:td>
                </xhtml:tr>
            </xforms:repeat>
        </xhtml:table>

This is the result I got. My question is how can I sort by the second column (name). This column doesn't exist in the repeat nodeset, but I can get it from other instance because there is fk in nodeset. It is a lookup. Does exf:sort provide solution of this situation? Could you check it?

fk   name score

p1  Tom  90  

p2  Jack  100  

p3  Clark  80  

p4  Mike  70  

   
Thank you very much!

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RE: Re: Can I sort by the label (ref by the value in xml) in exf:sort function

James Gu


You solution can solve the problem in this example. You changed the nodeset from employee to persons, but in my real cases, there are multiple reference columns and I need to keep the employee as nodeset. What I want is to provide user the ability to sort by reference columns.

What I want is something like this:

<xforms:repeat nodeset="exf:sort(xxforms:instance('scorelist')/employee,  'xxforms:instance(''personlist'')/Person[@key=current()/personfk]/PersonName/FullName' ,'text')">

Unfortunately, current() function can not be used in xpath.


<xhtml:table>
            <xforms:repeat
nodeset="exf:sort(xxforms:instance('personlist')/Person,'PersonName/FullName','text')">
                <xhtml:tr>
                    <xhtml:td>
                        <xforms:output value="@key"></xforms:output>
                    </xhtml:td>
                    <xhtml:td>
                        <xforms:output value="PersonName/Fullname"></xforms:output>
                    </xhtml:td>
                    <xhtml:td>
                        <xforms:output value="xxforms:instance('scorelist')/employee[personfk = current()/@key]/score"></xforms:output>
                    </xhtml:td>
                </xhtml:tr>
            </xforms:repeat>
        </xhtml:table>

Ryan

-----------------------------------------------
Ryan Puddephatt
FIX Developer
Fidessa LatentZero
1 Alfred Place
London WC1E 7EB
Office: +44 (0) 20 7462 4200
Direct: +44 (0) 20 7323 6112
Blackberry: +44 (0) 79 8539 2458
Fax: +44 (0) 20 7462 4242
Email: rpuddephatt@latentzero.com
Web: http://www.latentzero.com


-----Original Message-----
From: JamesGu [mailto:jxgu@cnsh.delphi-tech.com]
Sent: 20 June 2008 22:52
To: ops-users@ow2.org
Subject: [ops-users] Re: Can I sort by the label (ref by the value in xml) in exf:sort function


These are the instances.
            <xforms:instance id="scorelist">
                <department>
                    <employee>
                        <personfk>p3</personfk>
                        <score>80</score>
                    </employee>
                    <employee>
                        <personfk>p4</personfk>
                        <score>70</score>
                    </employee>
                    <employee>
                        <personfk>p1</personfk>
                        <score>90</score>
                    </employee>
                    <employee>
                        <personfk>p2</personfk>
                        <score>100</score>
                    </employee>
                </department>
            </xforms:instance>

            <xforms:instance id="personlist">
                <persons>
                    <Person key="p1">
                        <PersonName>
                            <FullName>Tom</FullName>
                        </PersonName>
                    </Person>
                    <Person key="p2">
                        <PersonName>
                            <FullName>Jack</FullName>
                        </PersonName>
                    </Person>
                    <Person key="p3">
                        <PersonName>
                            <FullName>Clark</FullName>
                        </PersonName>
                    </Person>
                    <Person key="p4">
                        <PersonName>
                            <FullName>Mike</FullName>
                        </PersonName>
                    </Person>
                </persons>
            </xforms:instance>


This is the code to generate a table for instance list.

        <xhtml:table>
            <xforms:repeat
nodeset="exf:sort(xxforms:instance('scorelist')/employee,'personfk','text')">
                <xhtml:tr>
                    <xhtml:td>
                        <xforms:output value="personfk"></xforms:output>
                    </xhtml:td>
                    <xhtml:td>
                        <xxforms:variable name="current-value"
select="personfk"></xxforms:variable>
                        <xforms:output
                               
value="saxon:evaluate(replace('xxforms:instance(''personlist'')/Person[@key=''%current-value%'']/PersonName/FullName',
'%current-value%', $current-value))"></xforms:output>
                    </xhtml:td>
                    <xhtml:td>
                        <xforms:output value="score"></xforms:output>
                    </xhtml:td>
                </xhtml:tr>
            </xforms:repeat>
        </xhtml:table>

This is the result I got. My question is how can I sort by the second column (name). This column doesn't exist in the repeat nodeset, but I can get it from other instance because there is fk in nodeset. It is a lookup. Does exf:sort provide solution of this situation? Could you check it?

fk   name score

p1  Tom  90  

p2  Jack  100  

p3  Clark  80  

p4  Mike  70  

   
Thank you very much!

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View this message in context: http://www.nabble.com/Can-I-sort-by-the-label-%28ref-by-the-value-in-xml%29-in-exf%3Asort-function-tp17867017p18037995.html
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RE: Re: Can I sort by the label (ref by the value in xml) in exf:sort function

Mike Ahlers
Hi James,

What comes to my mind is to wrap triggers around each of the columns you want to be sortable, and pass it to a pipeline where you do xslt sorting, where in fact, you replace the data sorted. The page itself would remain simple as the data is sorted to start with. Maybe this approach is the hard way and it could be solved 'inline'...

Just my few cents,
Mike
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Re: RE: Re: Can I sort by the label (ref by the value in xml) in exf:sort function

Ryan Puddephatt-3
In reply to this post by James Gu
You could use a XPL to process the sort using XSLT

I think this is going to be the easiest way
------------------------
Ryan Puddephatt
FIX Developer
Fidessa LatentZero
1 Alfred Place
London WC1E 7EB
Office: +44 (0) 20 7462 4200
Direct: +44 (0) 20 7323 6112
Blackberry: +44 (0) 79 8539 2458
Fax: +44 (0) 20 7462 4242
Email: [hidden email]
Web: http://www.latentzero.com
Sent from my blackberry device

----- Original Message -----
From: JamesGu <[hidden email]>
To: [hidden email] <[hidden email]>
Sent: Mon Jun 23 20:07:37 2008
Subject: [ops-users] RE: Re: Can I sort by the label (ref by the value in xml) in exf:sort function




You solution can solve the problem in this example. You changed the nodeset
from employee to persons, but in my real cases, there are multiple reference
columns and I need to keep the employee as nodeset. What I want is to
provide user the ability to sort by reference columns.

What I want is something like this:

<xforms:repeat nodeset="exf:sort(xxforms:instance('scorelist')/employee,
'xxforms:instance(''personlist'')/Person[@key=current()/personfk]/PersonName/FullName'
,'text')">

Unfortunately, current() function can not be used in xpath.


<xhtml:table>
            <xforms:repeat
nodeset="exf:sort(xxforms:instance('personlist')/Person,'PersonName/FullName','text')">
                <xhtml:tr>
                    <xhtml:td>
                        <xforms:output value="@key"></xforms:output>
                    </xhtml:td>
                    <xhtml:td>
                        <xforms:output
value="PersonName/Fullname"></xforms:output>
                    </xhtml:td>
                    <xhtml:td>
                        <xforms:output
value="xxforms:instance('scorelist')/employee[personfk =
current()/@key]/score"></xforms:output>
                    </xhtml:td>
                </xhtml:tr>
            </xforms:repeat>
        </xhtml:table>

Ryan

-----------------------------------------------
Ryan Puddephatt
FIX Developer
Fidessa LatentZero
1 Alfred Place
London WC1E 7EB
Office: +44 (0) 20 7462 4200
Direct: +44 (0) 20 7323 6112
Blackberry: +44 (0) 79 8539 2458
Fax: +44 (0) 20 7462 4242
Email: [hidden email]
Web: http://www.latentzero.com


-----Original Message-----
From: JamesGu [mailto:[hidden email]]
Sent: 20 June 2008 22:52
To: [hidden email]
Subject: [ops-users] Re: Can I sort by the label (ref by the value in xml)
in exf:sort function


These are the instances.
            <xforms:instance id="scorelist">
                <department>
                    <employee>
                        <personfk>p3</personfk>
                        <score>80</score>
                    </employee>
                    <employee>
                        <personfk>p4</personfk>
                        <score>70</score>
                    </employee>
                    <employee>
                        <personfk>p1</personfk>
                        <score>90</score>
                    </employee>
                    <employee>
                        <personfk>p2</personfk>
                        <score>100</score>
                    </employee>
                </department>
            </xforms:instance>

            <xforms:instance id="personlist">
                <persons>
                    <Person key="p1">
                        <PersonName>
                            <FullName>Tom</FullName>
                        </PersonName>
                    </Person>
                    <Person key="p2">
                        <PersonName>
                            <FullName>Jack</FullName>
                        </PersonName>
                    </Person>
                    <Person key="p3">
                        <PersonName>
                            <FullName>Clark</FullName>
                        </PersonName>
                    </Person>
                    <Person key="p4">
                        <PersonName>
                            <FullName>Mike</FullName>
                        </PersonName>
                    </Person>
                </persons>
            </xforms:instance>


This is the code to generate a table for instance list.

        <xhtml:table>
            <xforms:repeat
nodeset="exf:sort(xxforms:instance('scorelist')/employee,'personfk','text')">
                <xhtml:tr>
                    <xhtml:td>
                        <xforms:output value="personfk"></xforms:output>
                    </xhtml:td>
                    <xhtml:td>
                        <xxforms:variable name="current-value"
select="personfk"></xxforms:variable>
                        <xforms:output
                               
value="saxon:evaluate(replace('xxforms:instance(''personlist'')/Person[@key=''%current-value%'']/PersonName/FullName',
'%current-value%', $current-value))"></xforms:output>
                    </xhtml:td>
                    <xhtml:td>
                        <xforms:output value="score"></xforms:output>
                    </xhtml:td>
                </xhtml:tr>
            </xforms:repeat>
        </xhtml:table>

This is the result I got. My question is how can I sort by the second column
(name). This column doesn't exist in the repeat nodeset, but I can get it
from other instance because there is fk in nodeset. It is a lookup. Does
exf:sort provide solution of this situation? Could you check it?

fk   name score

p1  Tom  90  

p2  Jack  100  

p3  Clark  80  

p4  Mike  70  

   
Thank you very much!

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RE: Re: Can I sort by the label (ref by the value in xml) in exf:sort function

James Gu
In reply to this post by Mike Ahlers
Mike,

Thank you very much! This works but I am worried that it will slow down the server when users do many sorts actions or there are too many records. I am trying to find a way to do sorting on client side.

Thanks,
James

Mike Ahlers wrote
Hi James,

What comes to my mind is to wrap triggers around each of the columns you want to be sortable, and pass it to a pipeline where you do xslt sorting, where in fact, you replace the data sorted. The page itself would remain simple as the data is sorted to start with. Maybe this approach is the hard way and it could be solved 'inline'...

Just my few cents,
Mike
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Re: RE: Re: Can I sort by the label (ref by the value in xml) in exf:sort function

James Gu
In reply to this post by Ryan Puddephatt-3
Ryan,

Seems you did some research on this. Thank you very much! This works but I am worried about the performance on server side. Is there some way to do this kind of sorting on client side? Even it is complicated.

Thanks,
James


Ryan Puddephatt-3 wrote
You could use a XPL to process the sort using XSLT

I think this is going to be the easiest way
------------------------
Ryan Puddephatt
FIX Developer
Fidessa LatentZero
1 Alfred Place
London WC1E 7EB
Office: +44 (0) 20 7462 4200
Direct: +44 (0) 20 7323 6112
Blackberry: +44 (0) 79 8539 2458
Fax: +44 (0) 20 7462 4242
Email: rpuddephatt@latentzero.com
Web: http://www.latentzero.com
Sent from my blackberry device

----- Original Message -----
From: JamesGu <jxgu@cnsh.delphi-tech.com>
To: ops-users@ow2.org <ops-users@ow2.org>
Sent: Mon Jun 23 20:07:37 2008
Subject: [ops-users] RE: Re: Can I sort by the label (ref by the value in xml) in exf:sort function




You solution can solve the problem in this example. You changed the nodeset
from employee to persons, but in my real cases, there are multiple reference
columns and I need to keep the employee as nodeset. What I want is to
provide user the ability to sort by reference columns.

What I want is something like this:

<xforms:repeat nodeset="exf:sort(xxforms:instance('scorelist')/employee,
'xxforms:instance(''personlist'')/Person[@key=current()/personfk]/PersonName/FullName'
,'text')">

Unfortunately, current() function can not be used in xpath.


<xhtml:table>
            <xforms:repeat
nodeset="exf:sort(xxforms:instance('personlist')/Person,'PersonName/FullName','text')">
                <xhtml:tr>
                    <xhtml:td>
                        <xforms:output value="@key"></xforms:output>
                    </xhtml:td>
                    <xhtml:td>
                        <xforms:output
value="PersonName/Fullname"></xforms:output>
                    </xhtml:td>
                    <xhtml:td>
                        <xforms:output
value="xxforms:instance('scorelist')/employee[personfk =
current()/@key]/score"></xforms:output>
                    </xhtml:td>
                </xhtml:tr>
            </xforms:repeat>
        </xhtml:table>

Ryan

-----------------------------------------------
Ryan Puddephatt
FIX Developer
Fidessa LatentZero
1 Alfred Place
London WC1E 7EB
Office: +44 (0) 20 7462 4200
Direct: +44 (0) 20 7323 6112
Blackberry: +44 (0) 79 8539 2458
Fax: +44 (0) 20 7462 4242
Email: rpuddephatt@latentzero.com
Web: http://www.latentzero.com


-----Original Message-----
From: JamesGu [mailto:jxgu@cnsh.delphi-tech.com]
Sent: 20 June 2008 22:52
To: ops-users@ow2.org
Subject: [ops-users] Re: Can I sort by the label (ref by the value in xml)
in exf:sort function


These are the instances.
            <xforms:instance id="scorelist">
                <department>
                    <employee>
                        <personfk>p3</personfk>
                        <score>80</score>
                    </employee>
                    <employee>
                        <personfk>p4</personfk>
                        <score>70</score>
                    </employee>
                    <employee>
                        <personfk>p1</personfk>
                        <score>90</score>
                    </employee>
                    <employee>
                        <personfk>p2</personfk>
                        <score>100</score>
                    </employee>
                </department>
            </xforms:instance>

            <xforms:instance id="personlist">
                <persons>
                    <Person key="p1">
                        <PersonName>
                            <FullName>Tom</FullName>
                        </PersonName>
                    </Person>
                    <Person key="p2">
                        <PersonName>
                            <FullName>Jack</FullName>
                        </PersonName>
                    </Person>
                    <Person key="p3">
                        <PersonName>
                            <FullName>Clark</FullName>
                        </PersonName>
                    </Person>
                    <Person key="p4">
                        <PersonName>
                            <FullName>Mike</FullName>
                        </PersonName>
                    </Person>
                </persons>
            </xforms:instance>


This is the code to generate a table for instance list.

        <xhtml:table>
            <xforms:repeat
nodeset="exf:sort(xxforms:instance('scorelist')/employee,'personfk','text')">
                <xhtml:tr>
                    <xhtml:td>
                        <xforms:output value="personfk"></xforms:output>
                    </xhtml:td>
                    <xhtml:td>
                        <xxforms:variable name="current-value"
select="personfk"></xxforms:variable>
                        <xforms:output
                               
value="saxon:evaluate(replace('xxforms:instance(''personlist'')/Person[@key=''%current-value%'']/PersonName/FullName',
'%current-value%', $current-value))"></xforms:output>
                    </xhtml:td>
                    <xhtml:td>
                        <xforms:output value="score"></xforms:output>
                    </xhtml:td>
                </xhtml:tr>
            </xforms:repeat>
        </xhtml:table>

This is the result I got. My question is how can I sort by the second column
(name). This column doesn't exist in the repeat nodeset, but I can get it
from other instance because there is fk in nodeset. It is a lookup. Does
exf:sort provide solution of this situation? Could you check it?

fk   name score

p1  Tom  90  

p2  Jack  100  

p3  Clark  80  

p4  Mike  70  

   
Thank you very much!

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Re: Re: RE: Re: Can I sort by the label (ref by the value in xml) in exf:sort function

Erik Bruchez
Administrator
You could sort data on the client, but this raises an issue of keeping  
client and server in sync.

E.g. if you use xforms:repeat, the server assumes it knows in which  
order the data is on the client. If you change it on the client  
without telling the server, you risk confusing the server later and  
get unpredictable results.

-Erik

On Jun 24, 2008, at 1:37 PM, JamesGu wrote:

>
> Ryan,
>
> Seems you did some research on this. Thank you very much! This works  
> but I
> am worried about the performance on server side. Is there some way  
> to do
> this kind of sorting on client side? Even it is complicated.
>
> Thanks,
> James
>
>
>
> Ryan Puddephatt-3 wrote:
>>
>> You could use a XPL to process the sort using XSLT
>>
>> I think this is going to be the easiest way
>> ------------------------
>> Ryan Puddephatt
>> FIX Developer
>> Fidessa LatentZero
>> 1 Alfred Place
>> London WC1E 7EB
>> Office: +44 (0) 20 7462 4200
>> Direct: +44 (0) 20 7323 6112
>> Blackberry: +44 (0) 79 8539 2458
>> Fax: +44 (0) 20 7462 4242
>> Email: [hidden email]
>> Web: http://www.latentzero.com
>> Sent from my blackberry device
>>
>> ----- Original Message -----
>> From: JamesGu <[hidden email]>
>> To: [hidden email] <[hidden email]>
>> Sent: Mon Jun 23 20:07:37 2008
>> Subject: [ops-users] RE: Re: Can I sort by the label (ref by the  
>> value in
>> xml) in exf:sort function
>>
>>
>>
>>
>> You solution can solve the problem in this example. You changed the
>> nodeset
>> from employee to persons, but in my real cases, there are multiple
>> reference
>> columns and I need to keep the employee as nodeset. What I want is to
>> provide user the ability to sort by reference columns.
>>
>> What I want is something like this:
>>
>> <xforms:repeat nodeset="exf:sort(xxforms:instance('scorelist')/
>> employee,
>> 'xxforms:instance(''personlist'')/Person[@key=current()/personfk]/
>> PersonName/FullName'
>> ,'text')">
>>
>> Unfortunately, current() function can not be used in xpath.
>>
>>
>> <xhtml:table>
>>            <xforms:repeat
>> nodeset="exf:sort(xxforms:instance('personlist')/Person,'PersonName/
>> FullName','text')">
>>                <xhtml:tr>
>>                    <xhtml:td>
>>                        <xforms:output value="@key"></xforms:output>
>>                    </xhtml:td>
>>                    <xhtml:td>
>>                        <xforms:output
>> value="PersonName/Fullname"></xforms:output>
>>                    </xhtml:td>
>>                    <xhtml:td>
>>                        <xforms:output
>> value="xxforms:instance('scorelist')/employee[personfk =
>> current()/@key]/score"></xforms:output>
>>                    </xhtml:td>
>>                </xhtml:tr>
>>            </xforms:repeat>
>>        </xhtml:table>
>>
>> Ryan
>>
>> -----------------------------------------------
>> Ryan Puddephatt
>> FIX Developer
>> Fidessa LatentZero
>> 1 Alfred Place
>> London WC1E 7EB
>> Office: +44 (0) 20 7462 4200
>> Direct: +44 (0) 20 7323 6112
>> Blackberry: +44 (0) 79 8539 2458
>> Fax: +44 (0) 20 7462 4242
>> Email: [hidden email]
>> Web: http://www.latentzero.com
>>
>>
>> -----Original Message-----
>> From: JamesGu [mailto:[hidden email]]
>> Sent: 20 June 2008 22:52
>> To: [hidden email]
>> Subject: [ops-users] Re: Can I sort by the label (ref by the value  
>> in xml)
>> in exf:sort function
>>
>>
>> These are the instances.
>>            <xforms:instance id="scorelist">
>>                <department>
>>                    <employee>
>>                        <personfk>p3</personfk>
>>                        <score>80</score>
>>                    </employee>
>>                    <employee>
>>                        <personfk>p4</personfk>
>>                        <score>70</score>
>>                    </employee>
>>                    <employee>
>>                        <personfk>p1</personfk>
>>                        <score>90</score>
>>                    </employee>
>>                    <employee>
>>                        <personfk>p2</personfk>
>>                        <score>100</score>
>>                    </employee>
>>                </department>
>>            </xforms:instance>
>>
>>            <xforms:instance id="personlist">
>>                <persons>
>>                    <Person key="p1">
>>                        <PersonName>
>>                            <FullName>Tom</FullName>
>>                        </PersonName>
>>                    </Person>
>>                    <Person key="p2">
>>                        <PersonName>
>>                            <FullName>Jack</FullName>
>>                        </PersonName>
>>                    </Person>
>>                    <Person key="p3">
>>                        <PersonName>
>>                            <FullName>Clark</FullName>
>>                        </PersonName>
>>                    </Person>
>>                    <Person key="p4">
>>                        <PersonName>
>>                            <FullName>Mike</FullName>
>>                        </PersonName>
>>                    </Person>
>>                </persons>
>>            </xforms:instance>
>>
>>
>> This is the code to generate a table for instance list.
>>
>>        <xhtml:table>
>>            <xforms:repeat
>> nodeset="exf:sort(xxforms:instance('scorelist')/
>> employee,'personfk','text')">
>>                <xhtml:tr>
>>                    <xhtml:td>
>>                        <xforms:output value="personfk"></
>> xforms:output>
>>                    </xhtml:td>
>>                    <xhtml:td>
>>                        <xxforms:variable name="current-value"
>> select="personfk"></xxforms:variable>
>>                        <xforms:output
>>
>> value="saxon:evaluate(replace('xxforms:instance(''personlist'')/
>> Person[@key=''%current-value%'']/PersonName/FullName',
>> '%current-value%', $current-value))"></xforms:output>
>>                    </xhtml:td>
>>                    <xhtml:td>
>>                        <xforms:output value="score"></xforms:output>
>>                    </xhtml:td>
>>                </xhtml:tr>
>>            </xforms:repeat>
>>        </xhtml:table>
>>
>> This is the result I got. My question is how can I sort by the second
>> column
>> (name). This column doesn't exist in the repeat nodeset, but I can  
>> get it
>> from other instance because there is fk in nodeset. It is a lookup.  
>> Does
>> exf:sort provide solution of this situation? Could you check it?
>>
>> fk   name score
>>
>> p1  Tom  90
>>
>> p2  Jack  100
>>
>> p3  Clark  80
>>
>> p4  Mike  70
>>
>>
>> Thank you very much!
>>
>> --
>> View this message in context:
>> http://www.nabble.com/Can-I-sort-by-the-label-%28ref-by-the-value-in-xml%29-in-exf%3Asort-function-tp17867017p18037995.html
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Re: Re: Re: RE: Re: Can I sort by the label (ref by the value in xml) in exf:sort function

Ryan Puddephatt-3
In reply to this post by James Gu
Erik/James,
   I agree I've done some testing with this in the past and found javascript sorting caused a number of problems for the server

Running an XSL on the server is pretty fast, if not equally as fast as your current sort method, which is also processed server-side

Ryan
------------------------
Ryan Puddephatt
FIX Developer
Fidessa LatentZero
1 Alfred Place
London WC1E 7EB
Office: +44 (0) 20 7462 4200
Direct: +44 (0) 20 7323 6112
Blackberry: +44 (0) 79 8539 2458
Fax: +44 (0) 20 7462 4242
Email: [hidden email]
Web: http://www.latentzero.com
Sent from my blackberry device

----- Original Message -----
From: Erik Bruchez <[hidden email]>
To: [hidden email] <[hidden email]>
Sent: Wed Jun 25 17:27:40 2008
Subject: [ops-users] Re: Re: RE: Re: Can I sort by the label (ref by the value in xml) in exf:sort function

You could sort data on the client, but this raises an issue of keeping  
client and server in sync.

E.g. if you use xforms:repeat, the server assumes it knows in which  
order the data is on the client. If you change it on the client  
without telling the server, you risk confusing the server later and  
get unpredictable results.

-Erik

On Jun 24, 2008, at 1:37 PM, JamesGu wrote:

>
> Ryan,
>
> Seems you did some research on this. Thank you very much! This works  
> but I
> am worried about the performance on server side. Is there some way  
> to do
> this kind of sorting on client side? Even it is complicated.
>
> Thanks,
> James
>
>
>
> Ryan Puddephatt-3 wrote:
>>
>> You could use a XPL to process the sort using XSLT
>>
>> I think this is going to be the easiest way
>> ------------------------
>> Ryan Puddephatt
>> FIX Developer
>> Fidessa LatentZero
>> 1 Alfred Place
>> London WC1E 7EB
>> Office: +44 (0) 20 7462 4200
>> Direct: +44 (0) 20 7323 6112
>> Blackberry: +44 (0) 79 8539 2458
>> Fax: +44 (0) 20 7462 4242
>> Email: [hidden email]
>> Web: http://www.latentzero.com
>> Sent from my blackberry device
>>
>> ----- Original Message -----
>> From: JamesGu <[hidden email]>
>> To: [hidden email] <[hidden email]>
>> Sent: Mon Jun 23 20:07:37 2008
>> Subject: [ops-users] RE: Re: Can I sort by the label (ref by the  
>> value in
>> xml) in exf:sort function
>>
>>
>>
>>
>> You solution can solve the problem in this example. You changed the
>> nodeset
>> from employee to persons, but in my real cases, there are multiple
>> reference
>> columns and I need to keep the employee as nodeset. What I want is to
>> provide user the ability to sort by reference columns.
>>
>> What I want is something like this:
>>
>> <xforms:repeat nodeset="exf:sort(xxforms:instance('scorelist')/
>> employee,
>> 'xxforms:instance(''personlist'')/Person[@key=current()/personfk]/
>> PersonName/FullName'
>> ,'text')">
>>
>> Unfortunately, current() function can not be used in xpath.
>>
>>
>> <xhtml:table>
>>            <xforms:repeat
>> nodeset="exf:sort(xxforms:instance('personlist')/Person,'PersonName/
>> FullName','text')">
>>                <xhtml:tr>
>>                    <xhtml:td>
>>                        <xforms:output value="@key"></xforms:output>
>>                    </xhtml:td>
>>                    <xhtml:td>
>>                        <xforms:output
>> value="PersonName/Fullname"></xforms:output>
>>                    </xhtml:td>
>>                    <xhtml:td>
>>                        <xforms:output
>> value="xxforms:instance('scorelist')/employee[personfk =
>> current()/@key]/score"></xforms:output>
>>                    </xhtml:td>
>>                </xhtml:tr>
>>            </xforms:repeat>
>>        </xhtml:table>
>>
>> Ryan
>>
>> -----------------------------------------------
>> Ryan Puddephatt
>> FIX Developer
>> Fidessa LatentZero
>> 1 Alfred Place
>> London WC1E 7EB
>> Office: +44 (0) 20 7462 4200
>> Direct: +44 (0) 20 7323 6112
>> Blackberry: +44 (0) 79 8539 2458
>> Fax: +44 (0) 20 7462 4242
>> Email: [hidden email]
>> Web: http://www.latentzero.com
>>
>>
>> -----Original Message-----
>> From: JamesGu [mailto:[hidden email]]
>> Sent: 20 June 2008 22:52
>> To: [hidden email]
>> Subject: [ops-users] Re: Can I sort by the label (ref by the value  
>> in xml)
>> in exf:sort function
>>
>>
>> These are the instances.
>>            <xforms:instance id="scorelist">
>>                <department>
>>                    <employee>
>>                        <personfk>p3</personfk>
>>                        <score>80</score>
>>                    </employee>
>>                    <employee>
>>                        <personfk>p4</personfk>
>>                        <score>70</score>
>>                    </employee>
>>                    <employee>
>>                        <personfk>p1</personfk>
>>                        <score>90</score>
>>                    </employee>
>>                    <employee>
>>                        <personfk>p2</personfk>
>>                        <score>100</score>
>>                    </employee>
>>                </department>
>>            </xforms:instance>
>>
>>            <xforms:instance id="personlist">
>>                <persons>
>>                    <Person key="p1">
>>                        <PersonName>
>>                            <FullName>Tom</FullName>
>>                        </PersonName>
>>                    </Person>
>>                    <Person key="p2">
>>                        <PersonName>
>>                            <FullName>Jack</FullName>
>>                        </PersonName>
>>                    </Person>
>>                    <Person key="p3">
>>                        <PersonName>
>>                            <FullName>Clark</FullName>
>>                        </PersonName>
>>                    </Person>
>>                    <Person key="p4">
>>                        <PersonName>
>>                            <FullName>Mike</FullName>
>>                        </PersonName>
>>                    </Person>
>>                </persons>
>>            </xforms:instance>
>>
>>
>> This is the code to generate a table for instance list.
>>
>>        <xhtml:table>
>>            <xforms:repeat
>> nodeset="exf:sort(xxforms:instance('scorelist')/
>> employee,'personfk','text')">
>>                <xhtml:tr>
>>                    <xhtml:td>
>>                        <xforms:output value="personfk"></
>> xforms:output>
>>                    </xhtml:td>
>>                    <xhtml:td>
>>                        <xxforms:variable name="current-value"
>> select="personfk"></xxforms:variable>
>>                        <xforms:output
>>
>> value="saxon:evaluate(replace('xxforms:instance(''personlist'')/
>> Person[@key=''%current-value%'']/PersonName/FullName',
>> '%current-value%', $current-value))"></xforms:output>
>>                    </xhtml:td>
>>                    <xhtml:td>
>>                        <xforms:output value="score"></xforms:output>
>>                    </xhtml:td>
>>                </xhtml:tr>
>>            </xforms:repeat>
>>        </xhtml:table>
>>
>> This is the result I got. My question is how can I sort by the second
>> column
>> (name). This column doesn't exist in the repeat nodeset, but I can  
>> get it
>> from other instance because there is fk in nodeset. It is a lookup.  
>> Does
>> exf:sort provide solution of this situation? Could you check it?
>>
>> fk   name score
>>
>> p1  Tom  90
>>
>> p2  Jack  100
>>
>> p3  Clark  80
>>
>> p4  Mike  70
>>
>>
>> Thank you very much!
>>
>> --
>> View this message in context:
>> http://www.nabble.com/Can-I-sort-by-the-label-%28ref-by-the-value-in-xml%29-in-exf%3Asort-function-tp17867017p18037995.html
>> Sent from the ObjectWeb OPS - Users mailing list archive at  
>> Nabble.com.
>>
>>
>>
>> ______________________________________________________________________
>> This email has been scanned by the MessageLabs Email Security System.
>> For more information please visit http://www.messagelabs.com/email
>> ______________________________________________________________________
>>
>> _______________________________________________________________________
>> The information transmitted is intended only for the person or  
>> entity to
>> which it is addressed and may contain confidential and/or privileged
>> material. Any review, retransmission, dissemination or other use  
>> of, or
>> taking of any action in reliance upon, this information by persons or
>> entities other than the intended recipient is prohibited. If you  
>> received
>> this in error, please contact the sender and delete the material  
>> from any
>> computer.
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